(-7a^2b^3c^0/3a^3b^4c^3)^-4

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Solution for (-7a^2b^3c^0/3a^3b^4c^3)^-4 equation: 


D( x )

a^3*((-7*c^0*a^2*b^3)/3)*b^4*c^3 = 0

a^3*((-7*c^0*a^2*b^3)/3)*b^4*c^3 = 0

a^3*((-7*c^0*a^2*b^3)/3)*b^4*c^3 = 0

a^3*((-7*a^2*b^3)/3)*b^4*c^3 = 0

-7/3*a^5*b^7*c^3 = 0

x naleu017Cy do R

x belongs to the empty set

(a^3*((-7*c^0*a^2*b^3)/3)*b^4*c^3)^-4 = 0

x belongs to the empty set

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